910. Smallest Range II
Given an array A
of integers, for each integer A[i]
we need to choose either x = -K
or x = K
, and add x
to A[i] **(only once)**
.
After this process, we have some array B
.
Return the smallest possible difference between the maximum value of B
and the minimum value of B
.
Example 1:
Input: A = [1], K = 0
Output: 0
**Explanation** : B = [1]
Example 2:
Input: A = [0,10], K = 2
Output: 6
**Explanation** : B = [2,8]
Example 3:
Input: A = [1,3,6], K = 3
Output: 3
**Explanation** : B = [4,6,3]
Note:
1 <= A.length <= 10000
0 <= A[i] <= 10000
0 <= K <= 10000
# @lc code=start
using LeetCode
function smallest_rangeII(nums::Vector{Int}, k::Integer)
sort!(nums)
res = nums[end] - nums[1]
for i in 2:length(nums)
res = min(res, max(nums[end] - k, nums[i - 1] + k) - min(nums[1] + k, nums[i] - k))
end
return res
end
# @lc code=end
smallest_rangeII (generic function with 1 method)
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