910. Smallest Range II

Source code notebook Author Update time

Given an array A of integers, for each integer A[i] we need to choose either x = -K or x = K, and add x to A[i] **(only once)**.

After this process, we have some array B.

Return the smallest possible difference between the maximum value of B and the minimum value of B.

Example 1:

Input: A = [1], K = 0
Output: 0
**Explanation** : B = [1]

Example 2:

Input: A = [0,10], K = 2
Output: 6
**Explanation** : B = [2,8]

Example 3:

Input: A = [1,3,6], K = 3
Output: 3
**Explanation** : B = [4,6,3]

Note:

  1. 1 <= A.length <= 10000
  2. 0 <= A[i] <= 10000
  3. 0 <= K <= 10000
# @lc code=start
using LeetCode

function smallest_rangeII(nums::Vector{Int}, k::Integer)
    sort!(nums)
    res = nums[end] - nums[1]
    for i in 2:length(nums)
        res = min(res, max(nums[end] - k, nums[i - 1] + k) - min(nums[1] + k, nums[i] - k))
    end
    return res
end
# @lc code=end
smallest_rangeII (generic function with 1 method)

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