482. License Key Formatting

Source code notebook Author Update time

You are given a license key represented as a string S which consists only alphanumeric character and dashes. The string is separated into N+1 groups by N dashes.

Given a number K, we would want to reformat the strings such that each group contains exactly K characters, except for the first group which could be shorter than K, but still must contain at least one character. Furthermore, there must be a dash inserted between two groups and all lowercase letters should be converted to uppercase.

Given a non-empty string S and a number K, format the string according to the rules described above.

Example 1:

Input: S = "5F3Z-2e-9-w", K = 4

Output: "5F3Z-2E9W"

Explanation: The string S has been split into two parts, each part has 4 characters.
Note that the two extra dashes are not needed and can be removed.

Example 2:

Input: S = "2-5g-3-J", K = 2

Output: "2-5G-3J"

Explanation: The string S has been split into three parts, each part has 2 characters except the first part as it could be shorter as mentioned above.

Note:

  1. The length of string S will not exceed 12,000, and K is a positive integer.
  2. String S consists only of alphanumerical characters (a-z and/or A-Z and/or 0-9) and dashes(-).
  3. String S is non-empty.
# @lc code=start
using LeetCode

function license_key_formatting(S::String, K::Int)
    res = ""
    cnt = 0
    for i in length(S):-1:1
        if cnt == K
            res *= '-'
            cnt = 0
        end
        if S[i] != '-'
            res *= uppercase(S[i])
            cnt += 1
        end
    end
    reverse(res)
end
# @lc code=end
license_key_formatting (generic function with 1 method)

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