40. Combination Sum II

Source code notebook Author Update time

Given a collection of candidate numbers (candidates) and a target number (target), find all unique combinations in candidates where the candidate numbers sum to target.

Each number in candidates may only be used once in the combination.

Note: The solution set must not contain duplicate combinations.

Example 1:

Input: candidates = [10,1,2,7,6,1,5], target = 8
Output:
[
[1,1,6],
[1,2,5],
[1,7],
[2,6]
]

Example 2:

Input: candidates = [2,5,2,1,2], target = 5
Output:
[
[1,2,2],
[5]
]

Constraints:

  • 1 <= candidates.length <= 100
  • 1 <= candidates[i] <= 50
  • 1 <= target <= 30
# @lc code=start
using LeetCode

function combinationSum(candidates::AbstractVector{Int}, target::Int)
    res = Vector{Vector{Int}}()
    return combinationSum!(sort(candidates), target, Int[], res)
end

function combinationSum!(
    candidates::AbstractVector{Int},
    target::Int,
    path::AbstractVector{Int},
    res::Vector{Vector{Int}},
)

if the target is 0, we find a solution

    target == 0 && return push!(res, copy(path))
    length(candidates) == 0 || target < first(candidates) && return res

use @view to avoid copying the array

    for (i, candidate) in enumerate(candidates)
        i > 1 && candidate == candidates[i - 1] && continue
        candidate > target && break
        subcandidates = @view(candidates[1:length(candidate) .!= i]) # skip the current candidate
        combinationSum!(subcandidates, target - candidate, push!(path, candidate), res)
    end
    return res
end

# @lc code=end

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