645. Set Mismatch
The set S
originally contains numbers from 1 to n
. But unfortunately, due to the data error, one of the numbers in the set got duplicated to another number in the set, which results in repetition of one number and loss of another number.
Given an array nums
representing the data status of this set after the error. Your task is to firstly find the number occurs twice and then find the number that is missing. Return them in the form of an array.
Example 1:
Input: nums = [1,2,2,4]
Output: [2,3]
Note:
- The given array size will in the range [2, 10000].
- The given array's numbers won't have any order.
# @lc code=start
using LeetCode
function find_error_nums(nums::Vector{Int})
cnt = fill(0x0, length(nums))
for num in nums
cnt[num] += 1
end
return findfirst(==(0x2), cnt), findfirst(==(0x0), cnt)
end
# @lc code=end
find_error_nums (generic function with 1 method)
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