714. Best Time to Buy and Sell Stock with Transaction Fee

Source code notebook Author Update time

Your are given an array of integers prices, for which the i-th element is the price of a given stock on day i; and a non-negative integer fee representing a transaction fee.

You may complete as many transactions as you like, but you need to pay the transaction fee for each transaction. You may not buy more than 1 share of a stock at a time (ie. you must sell the stock share before you buy again.)

Return the maximum profit you can make.

Example 1:

Input: prices = [1, 3, 2, 8, 4, 9], fee = 2
Output: 8
Explanation: The maximum profit can be achieved by:

* Buying at prices[0] = 1
* Selling at prices[3] = 8
* Buying at prices[4] = 4
* Selling at prices[5] = 9
The total profit is ((8 - 1) - 2) + ((9 - 4) - 2) = 8.

Note:

  • 0 < prices.length <= 50000.
  • 0 < prices[i] < 50000.
  • 0 <= fee < 50000.
# @lc code=start
using LeetCode
function max_profit714(price::Vector{Int}, fee::Int)::Int
    dp1, dp2 = 0, -50000
    for p in price
        dp1, dp2 = max(dp1, dp2 + p - fee), max(dp2, dp1 - p)
    end
    return dp1
end
# @lc code=end
max_profit714 (generic function with 1 method)

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