2. Add Two Numbers

Source code notebook Author Update time

You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order , and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list.

You may assume the two numbers do not contain any leading zero, except the number 0 itself.

Example 1:

Input: l1 = [2,4,3], l2 = [5,6,4]
Output: [7,0,8]
Explanation: 342 + 465 = 807.

Example 2:

Input: l1 = [0], l2 = [0]
Output: [0]

Example 3:

Input: l1 = [9,9,9,9,9,9,9], l2 = [9,9,9,9]
Output: [8,9,9,9,0,0,0,1]

Constraints:

  • The number of nodes in each linked list is in the range [1, 100].
  • 0 <= Node.val <= 9
  • It is guaranteed that the list represents a number that does not have leading zeros.
# @lc code=start
using LeetCode

function add_two_numbers(l1::ListNode, l2::ListNode)::ListNode
    carry = 0
    fake_head = cur = ListNode()

    while !isnothing(l1) || !isnothing(l2) || !iszero(carry)
        v1, v2 = 0, 0

        if !isnothing(l1)
            v1 = val(l1)
            l1 = next(l1)
        end

        if !isnothing(l2)
            v2 = val(l2)
            l2 = next(l2)
        end

        carry, v = divrem(v1 + v2 + carry, 10)
        next!(cur, ListNode(v))
        cur = next(cur)
        val!(cur, v)
    end
    return next(fake_head)
end
# @lc code=end
add_two_numbers (generic function with 1 method)

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