1005. Maximize Sum Of Array After K Negations
Given an array A
of integers, we must modify the array in the following way: we choose an i
and replace A[i]
with -A[i]
, and we repeat this process K
times in total. (We may choose the same index i
multiple times.)
Return the largest possible sum of the array after modifying it in this way.
Example 1:
Input: A = [4,2,3], K = 1
Output: 5
Explanation: Choose indices (1,) and A becomes [4,-2,3].
Example 2:
Input: A = [3,-1,0,2], K = 3
Output: 6
Explanation: Choose indices (1, 2, 2) and A becomes [3,1,0,2].
Example 3:
Input: A = [2,-3,-1,5,-4], K = 2
Output: 13
Explanation: Choose indices (1, 4) and A becomes [2,3,-1,5,4].
Note:
1 <= A.length <= 10000
1 <= K <= 10000
-100 <= A[i] <= 100
# @lc code=start
using LeetCode
using DataStructures
function largest_sum_after_k_negations(A::Vector{Int}, K::Int)
total = sum(A)
pq = BinaryMinHeap(A)
for _ in 1:K
m = pop!(pq)
total -= 2 * m
push!(pq, -m)
end
total
end
# @lc code=end
largest_sum_after_k_negations (generic function with 1 method)
This page was generated using DemoCards.jl and Literate.jl.