674. Longest Continuous Increasing Subsequence
Given an unsorted array of integers nums
, return the length of the longest continuous increasing subsequence (i.e. subarray). The subsequence must be strictly increasing.
A continuous increasing subsequence is defined by two indices l
and r
(l < r
) such that it is [nums[l], nums[l + 1], ..., nums[r - 1], nums[r]]
and for each l <= i < r
, nums[i] < nums[i + 1]
.
Example 1:
Input: nums = [1,3,5,4,7]
Output: 3
Explanation: The longest continuous increasing subsequence is [1,3,5] with length 3.
Even though [1,3,5,7] is an increasing subsequence, it is not continuous as elements 5 and 7 are separated by element
4.
Example 2:
Input: nums = [2,2,2,2,2]
Output: 1
Explanation: The longest continuous increasing subsequence is [2] with length 1. Note that it must be strictly
increasing.
Constraints:
0 <= nums.length <= 104
-109 <= nums[i] <= 109
# @lc code=start
using LeetCode
function find_length_of_lcis(nums::Vector{Int})
res, tmp = 0, 1
for i in 2:length(nums)
if nums[i] > nums[i - 1]
tmp += 1
else
res = max(res, tmp)
tmp = 1
end
end
min(max(tmp, res), length(nums))
end
# @lc code=end
find_length_of_lcis (generic function with 1 method)
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