153. Find Minimum in Rotated Sorted Array
Suppose an array of length n
sorted in ascending order is rotated between 1
and n
times. For example, the array nums = [0,1,2,4,5,6,7]
might become:
[4,5,6,7,0,1,2]
if it was rotated4
times.[0,1,2,4,5,6,7]
if it was rotated7
times.
Notice that rotating an array [a[0], a[1], a[2], ..., a[n-1]]
1 time results in the array [a[n-1], a[0], a[1], a[2], ..., a[n-2]]
.
Given the sorted rotated array nums
, return the minimum element of this array.
Example 1:
Input: nums = [3,4,5,1,2]
Output: 1
Explanation: The original array was [1,2,3,4,5] rotated 3 times.
Example 2:
Input: nums = [4,5,6,7,0,1,2]
Output: 0
Explanation: The original array was [0,1,2,4,5,6,7] and it was rotated 4 times.
Example 3:
Input: nums = [11,13,15,17]
Output: 11
Explanation: The original array was [11,13,15,17] and it was rotated 4 times.
Constraints:
n == nums.length
1 <= n <= 5000
-5000 <= nums[i] <= 5000
- All the integers of
nums
are unique. nums
is sorted and rotated between1
andn
times.
# @lc code=start
using LeetCode
function find_min_153(nums::Vector{Int})
left, right = 1, length(nums)
while left < right
mid = (left + right) ÷ 2
(nums[mid] < nums[right]) ? (right = mid) : (left = mid + 1)
end
nums[left]
end
# @lc code=end
find_min_153 (generic function with 1 method)
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