892. Surface Area of 3D Shapes

On a N * N grid, we place some 1 * 1 * 1cubes.

Each value v = grid[i][j] represents a tower of v cubes placed on top of grid cell (i, j).

Return the total surface area of the resulting shapes.

Example 1:

Input: [[2]]
Output: 10

Example 2:

Input: [[1,2],[3,4]]
Output: 34

Example 3:

Input: [[1,0],[0,2]]
Output: 16

Example 4:

Input: [[1,1,1],[1,0,1],[1,1,1]]
Output: 32

Example 5:

Input: [[2,2,2],[2,1,2],[2,2,2]]
Output: 46

Note:

• 1 <= N <= 50
• 0 <= grid[i][j] <= 50

# @lc code=start
using LeetCode

function surface_area(grid::Vector{Vector{Int}})
    res = 2 * sum(sum(1 for i in row if i != 0) for row in grid)
    res += sum(row[1] + row[end] + sum(abs, diff(row)) for row in grid)
    return res += sum(grid[1][i] +
                      grid[end][i] +
                      ((length(grid) > 1) ?
                       (sum(abs(grid[row][i] - grid[row - 1][i]) for row in 2:length(grid))) :
                       0) for i in 1:length(grid[1]))
end
function surface_area(grid::Matrix{Int})
    res = 2 * sum(sum(1 for i in row if i != 0) for row in grid)
    res += sum(row[1] + row[end] + sum(abs, diff(row)) for row in eachrow(grid))
    res += sum(col[1] + col[end] + sum(abs, diff(col)) for col in eachcol(grid))
    res
end
# @lc code=end

surface_area (generic function with 2 methods)

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