599. Minimum Index Sum of Two Lists
Suppose Andy and Doris want to choose a restaurant for dinner, and they both have a list of favorite restaurants represented by strings.
You need to help them find out their common interest with the least list index sum. If there is a choice tie between answers, output all of them with no order requirement. You could assume there always exists an answer.
Example 1:
Input: list1 = ["Shogun","Tapioca Express","Burger King","KFC"], list2 = ["Piatti","The Grill at Torrey Pines","Hungry Hunter Steakhouse","Shogun"]
Output: ["Shogun"]
Explanation: The only restaurant they both like is "Shogun".
Example 2:
Input: list1 = ["Shogun","Tapioca Express","Burger King","KFC"], list2 = ["KFC","Shogun","Burger King"]
Output: ["Shogun"]
Explanation: The restaurant they both like and have the least index sum is "Shogun" with index sum 1 (0+1).
Example 3:
Input: list1 = ["Shogun","Tapioca Express","Burger King","KFC"], list2 = ["KFC","Burger King","Tapioca Express","Shogun"]
Output: ["KFC","Burger King","Tapioca Express","Shogun"]
Example 4:
Input: list1 = ["Shogun","Tapioca Express","Burger King","KFC"], list2 = ["KNN","KFC","Burger King","Tapioca Express","Shogun"]
Output: ["KFC","Burger King","Tapioca Express","Shogun"]
Example 5:
Input: list1 = ["KFC"], list2 = ["KFC"]
Output: ["KFC"]
Constraints:
1 <= list1.length, list2.length <= 1000
1 <= list1[i].length, list2[i].length <= 30
list1[i]
andlist2[i]
consist of spaces' '
and English letters.- All the stings of
list1
are unique. - All the stings of
list2
are unique.
# @lc code=start
using LeetCode
function find_restaurant(list1::Vector{String}, list2::Vector{String})::Vector{String}
dic = Dict(st => (i - 1) for (i, st) in enumerate(list1))
cost, res = typemax(1), String[]
for (i, s) in enumerate(list2)
!haskey(dic, s) && continue
newcost = i - 1 + dic[s]
if newcost < cost
cost, res = newcost, [s]
elseif newcost == cost
push!(res, s)
end
end
return res
end
# @lc code=end
find_restaurant (generic function with 1 method)
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