720. Longest Word in Dictionary

Source code notebook Author Update time

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest lexicographical order.

If there is no answer, return the empty string.

Example 1:

Input:
words = ["w","wo","wor","worl", "world"]
Output: "world"
Explanation:
The word "world" can be built one character at a time by "w", "wo", "wor", and "worl".

Example 2:

Input:
words = ["a", "banana", "app", "appl", "ap", "apply", "apple"]
Output: "apple"
Explanation:
Both "apply" and "apple" can be built from other words in the dictionary. However, "apple" is lexicographically smaller than "apply".

Note:

  • All the strings in the input will only contain lowercase letters.
  • The length of words will be in the range [1, 1000].
  • The length of words[i] will be in the range [1, 30].
# @lc code=start
using LeetCode

# use Trie
longest_common_word(words::Vector{String}) = longest_common_word!(words)
function longest_common_word!(words::Vector{String})::String
    root, res = Dict{Char,Dict}(), ""
    for word in sort!(words; by=length)
        node, n = root, length(word)
        for (i, c) in enumerate(word)
            if haskey(node, c)
                node = node[c]
            elseif i == n
                node[c] = Dict{Char,Dict}() ## add new child
                res = word
            else
                break
            end
        end
    end
    return res
end

# @lc code=end
longest_common_word! (generic function with 1 method)

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